Japan Academia · Research and learning

1964 result and a later lecture-based warm-up

Hironaka: What Can One Blow-Up Chart Show?

Read the scope of Hironaka’s characteristic-zero result, then compare two invented curve calculations without mistaking a local chart for a global proof.

Original learning diagram comparing two complex-curve substitutions,gradients and bounded conclusions.
Complex numbers
Field used in the exercise
One chart
Deliberate scope limit
A smooth; B singular
At the selected chart origin

The short answer

A visible cusp makes a large theorem approachable, but it also creates a trap: a successful local calculation may be mistaken for the theorem itself. Compare two chosen equations and keep three questions separate: transformation, smoothness and the arrangement of the exceptional set.

Compare the evidence

Three checks that should not be collapsed

The distinction is between the question asked and the evidence needed to answer it.

Selected comparison and original analysis; no research figure or complete source table is reproduced.
QuestionEvidence or calculationWhat remains open
SubstitutionCompute total and strict transformsDoes not by itself prove smoothness
GradientA: (−1, 0); B: (0, 0) at the originA pointwise check in one chart
Exceptional intersectionFor A, u = v² is tangent to u = 0Smoothness alone is not normal crossings

Chronology

A timeline of the turning points

  1. Characteristic-zero breakthrough

    The global result exceeds the classroom fixture.

  2. Compare two curves

    Inspect the transform and the exceptional intersection separately.

The global question behind the local picture

Hironaka’s result concerns algebraic varieties over characteristic-zero fields in arbitrary dimension. The IMU memorial describes a proper modification that leaves the smooth part unchanged.

Kollár’s selected lecture distinguishes resolution from stronger normal-crossing requirements and explains why local constructions must fit together globally. His later exposition is not the original 1964 proof.

The exercise below works over the complex numbers. It tests selected equations in one chart, not the existence or compatibility of all the modifications required by a general theorem.

Sources for this section: [1] · [2]

Define the chart and the objects being compared

In one blow-up chart at the plane origin, write x = u and y = uv. The exceptional divisor in this chart is u = 0. Substitution gives a total transform; removing the common exceptional factor gives the strict transform.

For this exercise, use the plane-curve gradient test: a point on F(u, v) = 0 is smooth when the two first partial derivatives do not both vanish. Check only the origin of this chart. Other charts and intersections still matter to a global or embedded resolution.

Sources for this section: [2]

An original pair of curve calculations

Take curve A: y² = x³. After substitution, u²v² = u³, so the total transform is u²(v²−u) = 0 and the strict transform is v²−u = 0. Find its gradient at (u, v) = (0, 0).

Take curve B: y² = x⁷. The same substitution gives u²(v²−u⁵) = 0 and strict transform v²−u⁵ = 0. Calculate the gradient at the origin. Which strict transform is smooth there? Does smoothness alone establish a transverse intersection with the exceptional divisor?

Sources for this section: [2]

Reference answer: one improvement and two limits

For A the gradient is (−1, 2v), hence (−1, 0) at the origin: the strict transform is smooth there. For B it is (−5u⁴, 2v), hence (0, 0): a singularity remains in this chart.

A still meets the exceptional line u = 0 tangentially: writing u = v² gives tangent line u = 0 at the origin. Thus smoothness of that strict transform is not by itself a normal-crossing conclusion. B demonstrates that the same substitution need not finish even the local smoothing task.

Neither calculation checks the other chart, a complete sequence, global patching or the arbitrary-dimensional theorem. They are useful because they expose those separate obligations, not because they replace Hironaka’s proof.

Sources for this section: [2]

Continue the chronology

Biography context

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Quick answers

Common questions

Does resolving one drawn cusp prove the theorem?
No. A particular curve calculation cannot establish the global arbitrary-dimensional result.

Primary and institutional sources

How this history was checked

Selected original passages and the stated reading scopes support the historical account. Every teaching fixture is explicitly invented. This article was reviewed on 30 October 2026.

  1. International Mathematical Union, IMU News 138, July 2026Heisuke Hironaka—singularities and the life of mathematics
  2. János Kollár / arXiv: math/0508332v3Resolution of Singularities—Seattle Lecture
  3. J. J. O’Connor and E. F. Robertson / University of St AndrewsHeisuke Hironaka: biography